A current carrying closed loop in the form of a right angle isosceles triangle $ABC$ is placed in a uniform magnetic field acting along $AB.$ If the magnetic force on the arm $BC$ is $\vec F,$ the force on the arm $AC$ is
A current carrying closed loop in the form of a right angle isosceles triangle $ABC$ is placed in a uniform magnetic field acting along $AB.$ If the magnetic force on the arm $BC$ is $\vec F,$ the force on the arm $AC$ is
- [AIPMT 2011]
- A
$ - \sqrt 2 \vec F$
- B
$-$ $\vec F$
- C
$\vec F$
- D
$\sqrt 2 \vec F$
Similar Questions
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Two parallel beams of electrons moving in the same direction produce a mutual force
A rectangular loop of wire shown below is coplanar with a long wire carrying current $I$. The loop is pulled to the right a s indicated. What are the directions of the induced current in the loop and the magnetic forces on the left and the right sides of the loop?
Induced current
Force on left side
Force on right side
$a.$
Counter clockwise
To the left
To the right
$b.$
clockwise
To the left
To the right
$c.$
Counter clockwise
To the right
To the left
$d.$
clockwise
To the right
To the left
A rectangular loop of wire shown below is coplanar with a long wire carrying current $I$. The loop is pulled to the right a s indicated. What are the directions of the induced current in the loop and the magnetic forces on the left and the right sides of the loop?
| Induced current | Force on left side | Force on right side | |
| $a.$ | Counter clockwise | To the left | To the right |
| $b.$ | clockwise | To the left | To the right |
| $c.$ | Counter clockwise | To the right | To the left |
| $d.$ | clockwise | To the right | To the left |
- [KVPY 2011]
A straight horizontal conducting rod of length $0.45\; m$ and mass $60\; g$ is suspended by two vertical wires at its ends. A current of $5.0 \;A$ is set up in the rod through the wires.
$(a)$ What magnetic field should be set up normal to the conductor in order that the tension in the wires is zero?
$(b)$ What will be the total tension in the wires if the direction of current is reversed keeping the magnetic field same as before? (Ignore the mass of the wires.) $g = 9.8\; m s^{-2}.$
A straight horizontal conducting rod of length $0.45\; m$ and mass $60\; g$ is suspended by two vertical wires at its ends. A current of $5.0 \;A$ is set up in the rod through the wires.
$(a)$ What magnetic field should be set up normal to the conductor in order that the tension in the wires is zero?
$(b)$ What will be the total tension in the wires if the direction of current is reversed keeping the magnetic field same as before? (Ignore the mass of the wires.) $g = 9.8\; m s^{-2}.$
A horizontal metallic rod of mass $'m'$ and length $'l'$ is supported by two vertical identical springs of spring of spring constant $'K'$ each and natural length $l_0.$ A current $'i'$ is flowing in the rod in the direction shown. If the rod is in equilibrium then the length of each spring in this state is :-
A horizontal metallic rod of mass $'m'$ and length $'l'$ is supported by two vertical identical springs of spring of spring constant $'K'$ each and natural length $l_0.$ A current $'i'$ is flowing in the rod in the direction shown. If the rod is in equilibrium then the length of each spring in this state is :-
Find force per unit length at $P$.
Find force per unit length at $P$.
- [AIIMS 2019]